Use that explanation to give a CFG for D(H) c, the match up of L(G).
![]() This principle generates chain starting with a, ending with c and middle will not contain a line ba. Hence L(G) have every string over a,b but not really the guitar strings of even duration whose middle(center) have ab. S i9000 aSb bSa áSa bSb ba l expect it to become correct, but in situation I are not after that please comment. Ill produce a string abdominal to illustrate this: H, Ya, aYa, áaYa, aabYa, aaba. Reply Delete Responses Answer Derek 21 Oct 2015 at 19:36 I believe you are incorrect. ![]() Right Remedy Delete Response Reply Unknown 19 Oct 2016 at 13:46 I think that the strings generated are all strings w whére w xyz and e 0 where back button is k as, z . is k bs, ánd y is ány string that stárts with b ór ends with á. Fundamentally all guitar strings that start with n or finish with a sandwichéd between ák bk Reply DeIete Replies Remedy hebroon 4 Apr 2017 at 16:53 I agree with L(G) will be the Unknowns. I think grammar of its complement: S i9000 - aSb áY Yb Y - bY aY RepIy Delete Replies Reply Insert comment Insert even more.
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